Select a property to see all associated equations. Properties represented with equations in TDE output are:


ln(p/po) = a1 + a2/T + a3×ln(T) + a4×T + a5×T2 + a6×T6+ a7/T4
ln(p/po) = a + b/T + c×ln(T) + d×T2 + e/T2 ; where po = 1 kPa
ln(p/po) = a + b/T + c×ln(T) + d×Te ; where po = 1 kPa
ln(p/po) – ln(pc/po) = Tc/T (A1×t + A2×t1.5 + A3×t3 + A4×t6); where t = 1 - T/Tc and po = 1 kPa


Evaluation Results:

The example is for fitted vapor pressures for benzene.


Evaluation Results:

The example is for fitted vapor pressures for benzene.


Evaluation Results:

The example is for fitted vapor pressures for benzene.


Evaluation Results:

The example is for fitted vapor pressures for benzene.


Evaluation Results:

The example is for fitted vapor pressures for benzene.


Evaluation Results:

The example is for fitted vapor pressures for benzene.


ln(p/po) = a1 + a2/T + a3×ln(T) + a4×T + a5×T2 + a6×T6+ a7/T4
ln(p/po) = A + B/(T + C); where po = 1 kPa
lg(p/po) = a + b/T + c×lg(T) + d×T + e/T2 ; where po = 1 kPa and lg = log10
ln(p/po) = a + b/T + c×ln(T) + d×T2 + e/T2 ; where po = 1 kPa
ln(p/po) = a + b/T + c×ln(T) + d×Te ; where po = 1 kPa



NOTE: The TDE program truncates this equation based upon the extent and quality of the fitted data.


p/po = å ai× T i, where the summation is from i = 0 to nTerms - 1 and po = 1 kPa.


Evaluation Results:

The example is for fitted phase-boundary pressures for benzene.


dsat = dc + a1×t0.35 + åai+1×ti , where the summation is from i = 1 to nTerms -1.
dc = the critical density and t = 1 - T/Tc, where Tc is the critical temperature.
dsat = dc×B– (1-T/Tc)N; where Tc and dc are the critical temperature and critical density, respectively.
dsat = dc + a1×t0.35 + a2×t2/3 + a3×t + a4×t4/3;
dc = the critical density and t = 1 - T/Tc, where Tc is the critical temperature.
dsat = (a1 + a2×t) -1 - t-2/7/a0 ; where t = 1 - T/Tc, and Tc is the critical temperature.


dc = the critical density and t = 1 - T/Tc, where Tc is the critical temperature.

NOTE: The TDE program truncates this equation based upon the extent and quality of the fitted data.
dc = the critical density and t = 1 - T/Tc, where Tc is the critical temperature.
Evaluation Results:

The example is for fitted densities at vapor saturation for benzene.


Evaluation Results:

The example is for fitted densities at vapor saturation for benzene.


dsat = dc + a1×t0.35 + åai+1×ti , where the summation is from i = 1 to nTerms -1.
dc = the critical density and t = 1 - T/Tc, where Tc is the critical temperature.


d = dsat / [1 - c×ln{(b + p) / (b + psat)}] ; where
b = åBi+1×t i,
c = åCi+1×t i, and
t = (T-Tcenter)/100, where Tcenter is a constant parameter.
Summations are from i = 0 to nTerms - 1, where nTerms is the number of B or C terms.
dsat = the density of the saturated liquid and psat = the saturation vapor pressure.


b = åBi+1×t i,
c = åCi+1×t i, and
t = (T-Tcenter)/100, where Tcenter is a constant parameter.
Summations are from i = 0 to nTerms - 1, where nTerms is the number of B or C terms.
dsat = the density of the saturated liquid and psat = the saturation vapor pressure.



d = 1000×Mw / Vm; where Mw is the molar mass and Vm is the molar volume.
Z = 1000×p×Vm/(R×T) = 1 + B/Vm + C/Vm2,
where B = åbi+1/T i, C = åci+1/T i, and R is the gas constant.


Z = 1000×p×Vm/(R×T) = 1 + B/Vm + C/Vm2,
where B = åbi+1/T i, C = åci+1/T i, and R is the gas constant.
Evaluation Results:

The example is for fitted gas densities of pentane.


ln(Hvap/Hvapo) = a1 + åai ×Tri-1×ln(1-Tr) , where the summation is from i = 2 to nTerms -1
Tr = T/Tc, Tc is the critical temperature, and Hvapo = 1 kJ/mol
Hvap = A×{1 - ( T / Tc )}n
Hvap/R = a1×t1/3 + a2×t2/3 + a3×t + a4×t2 + a5×t6
where t = 1 - T/Tc, Tc is the critical temperature, and R is the gas constant.


Tr = T/Tc, Tc is the critical temperature, and Hvapo = 1 kJ/mol
Evaluation Results:

The example is for fitted enthalpies of vaporization for benzene.


Evaluation Results:

The example is for fitted enthalpies of vaporization for pentane.


where t = 1 - T/Tc, Tc is the critical temperature, and R is the gas constant.
Evaluation Results:

The example is for fitted enthalpies of vaporization for benzene.


Csat = (åai+1× ti) + b/t , where the summation is from i = 0 to nTerms -1.
Csat = å ai× T i, where the summation is from i = 0 to nTerms - 1.
Csat = å ai× T i, where the summation is from i = 0 to nTerms - 1
Csat = å ai× T i, where the summation is from i = 0 to nTerms - 1
Csat / R = a0/t + a1 + a2×t + a3×t2 + a4×t3 + a5×t4
where t = 1 - T/Tc, Tc is the critical temperature, and R is the gas constant.


Csat = å ai× T i, where the summation is from i = 0 to nTerms - 1.
Csat = å ai× T i, where the summation is from i = 0 to nTerms - 1
Csat = å ai× T i, where the summation is from i = 0 to nTerms - 1


Evaluation Results:

The example is for fitted heat capacities at vapor saturation for quinoline.


Evaluation Results:

The example is for fitted heat capacities at vapor saturation for benzene.


Evaluation Results:

The example is for fitted heat capacities at vapor saturation for benzene.


Evaluation Results:

The example is for fitted heat capacities at vapor saturation for benzene.


where t = 1 - T/Tc, Tc is the critical temperature, and R is the gas constant.
Evaluation Results:

The example is for fitted heat capacities at vapor saturation for benzene.


Csat = å ai× T i, where the summation is from i = 0 to nTerms - 1.
Cpo = å ai× T i, where the summation is from i = 0 to nTerms - 1
Cpo = a + b×{(c/T)/sinh(c/T)}2 + d×{(e/T)/cosh(e/T)}2
Cpo/R = Clow + (Clow - C¥)×y2 ×{1 + (y - 1) å(ai × yi)} ; where the summation is from i = 0 to 4.
Clow and C¥ are equation constants, R is the gas constant, and y = T / (T + TS), where TS is a constant.
Cpo/R = 1 + t - {åai×ni×(ni - 1)×tni}(ni¹ 0 or 1) + åbi×(ci×t)2×exp(ci×t) / {exp(ci×t) - 1}2;
where t = Tc/T, Tc = the critical temperature, R is the gas constant, and the summations are from i = 1 to nTerms.



The example is for fitted heat capacities in the ideal-gas state at p = 100 kPa for pentane.


Reference: Aly, F. A.; Lee, L. L. Fluid Phase Equil. 1981, 6, 169-179.

The example is for fitted heat capacities in the ideal-gas state at p = 100 kPa for pentane.

Clow and C¥ are equation constants, and y = T / (T + TS), where TS is a constant.
Evaluation Results:

The example is for fitted heat capacities in the ideal-gas state at p = 100 kPa for pentane.





u = A + B×T + C×(d - dsat) + D×d 2,
where d is the density of the liquid and dsat is the density of the saturated liquid.


where d is the density of the liquid and dsat is the density of the saturated liquid.

The example is for fitted speeds of sound for benzene.


u = A + B×T + C×p + D×p/T ;
where T is the temperature and p is pressure.


where T is the temperature and p is pressure.

The example is for fitted speeds of sound for pentane in the gas phase.


nD = A + B×t + å Ci×wi ;the summation is from i = 1 to nTerms
where t = T - 298.15 K and w = WL - 589.26 (WL = wavelength in nm)


where t = T - 298.15 K and w = WL - 589.26 (WL = wavelength in nm)
Evaluation Results:

The example is for fitted surface tensions for pentane.


s = a0× ta1×(1 + a2 ×t) , where t = 1 - T/Tc and Tc is the critical temperature.
s = exp(A)×{1 - ( T / Tc )}n
ln(s/so) = a1 + åai ×Tri-1×ln(1-Tr) , where the summation is from i = 2 to nTerms -1
Tr = T/Tc, Tc is the critical temperature, and so = 1 N/m


Evaluation Results:

The example is for fitted surface tensions for benzene.


s = exp(A)×{1 - ( T / Tc )}n
Evaluation Results:

The example is for fitted surface tensions for benzene.


Tr = T/Tc, Tc is the critical temperature, and so = 1 N/m

The example is for fitted surface tensions for benzene.


ln(h/ho) = a1 ×X1/3 + a2 ×X4/3 + ln(a5) , where X = (a3 - T) / (T - a4) and ho = 1 Pa×s
lg(h/ho) = A + B/T + C×T + D×T 2
ln(h/ho) = a + b/T + c×ln(T) + d×Te ; where ho = 1 Pa×s


Evaluation Results:

The example is for fitted viscosities for the saturated liquid phase of benzene.


Evaluation Results:

The example is for fitted viscosities for the saturated liquid phase of benzene.


Evaluation Results:

The example is for fitted viscosities for the saturated liquid phase of benzene.


h = å ai× T i, where the summation is from i = 0 to nTerms - 1
h = å ai× T i, where the summation is from i = 0 to nTerms - 1
h = A×T B / (1+ C/T + D/T 2)
h = a0×Tr / {1 + a1×(Tr - 1)× Tra2}1/6; where Tr = T/Tc and Tc is the critical temperature.


Evaluation Results:

The example is for fitted thermal conductivities for the saturated liquid phase of pentane.


Evaluation Results:

The example is for fitted thermal conductivities for the saturated liquid phase of pentane.


Evaluation Results:

The example is for fitted thermal conductivities for the saturated liquid phase of pentane.


Evaluation Results:

The example is for fitted thermal conductivities for the saturated liquid phase of pentane.


l = å ai× T i, where the summation is from i = 0 to nTerms - 1
lg(l/lo) = A + B×(1 - T/C)2/7
l = å ai× T i, where the summation is from i = 0 to nTerms - 1
l = å ai× T i, where the summation is from i = 0 to nTerms - 1
l = a1 + å(ai+1 ×ti/3) , where the summation is from i = 1 to nTerms -1 and t = 1 - T/Tc


Evaluation Results:

The example is for fitted thermal conductivities for the saturated liquid phase of benzene.


Evaluation Results:

The example is for fitted thermal conductivities for the saturated liquid phase of benzene.


Evaluation Results:

The example is for fitted thermal conductivities for the saturated liquid phase of benzene.


Evaluation Results:

The example is for fitted thermal conductivities for the saturated liquid phase of benzene.


Evaluation Results:

The example is for fitted thermal conductivities for the liquid phase of benzene.


l = å ai× T i, where the summation is from i = 0 to nTerms - 1
l = å ai× T i, where the summation is from i = 0 to nTerms - 1
l = Tr0.5 (åai / Tri)-1 , where the summation is from i = 1 to 3,
and Tr = T/Tc, where Tc is the critical temperature.


Evaluation Results:

The example is for fitted thermal conductivities for the saturated liquid phase of pentane.


Evaluation Results:

The example is for fitted thermal conductivities for the saturated liquid phase of pentane.


and Tr = T/Tc, where Tc is the critical temperature.
Evaluation Results:

The example is for fitted thermal conductivities for the saturated liquid phase of pentane.

